下载app免费领取会员
Revit开发中AddinManager是一个非常好用的工具，它可以快速的运行我们写好的命令
并且生成addin文件，最近突然好奇，它是怎么实现这些功能的，然后研究了一下，
发现这里面似乎是通过反射来实现的，他能运行我们的写的命令最关键的是因为下面的代码
IExternalCommand externalCommand = assembly.CreateInstance(FullClassName) as IExternalCommand;
if (externalCommand != null)
{
result = externalCommand Execute( commandData, ref message, elements)
}
因为用反射创建我们写的命令的类之前，我们要先加载dll，而加载dl后，如果加载dll的位置和我们生成dll的位置相同
当我们再编译原来的工程就会失败，因为我们生成的dll要替换原来的dll，而原来的dll已经被占用，所有就会替换失败，
我想着就是AddInManager 运行命令之前，要先把dll文件复制到其他地方的原因吧
下面尝试些一个简单的AddInManager，并不包括将dll复制到其他地方，和生成addin文件的功能
//创建界面
public class MyApp:IExternalApplication
{
public Result OnShutdown(UIControlledApplication application)
{
return Result.Succeeded;
}
public Result OnStartup(UIControlledApplication application)
{
RibbonPanel panel = application.CreateRibbonPanel(Tab.AddIns, "NewAddInManager");
PushButtonData data = new PushButtonData("NewAddinManager", "MyCommand", this.GetType().Assembly.Location, "NewAddinManager.MyAddInCommand");
panel.AddItem(data);
return Result.Succeeded;
}
}
// addinManager 命令
public class MyAddInCommand : IExternalCommand
{
public string path = null;
public Result Execute(ExternalCommandData commandData, ref string message, ElementSet elements)
{
AppDomain.CurrentDomain.AssemblyResolve += LoadAssemble;
Result result;
OpenFileDialog dialog = new OpenFileDialog();
if (dialog.ShowDialog() == DialogResult.OK)
{
string file = dialog.FileName;
path = new FileInfo(file).DirectoryName;
Assembly ab = Assembly.LoadFile(file);
foreach (Type tp in ab.DefinedTypes)
{
IExternalCommand icmd = ab.CreateInstance(tp.FullName) as IExternalCommand;
if (icmd != null)
{
result = icmd.Execute(commandData, ref message, elements);
break;
}
}
}
return Result.Succeeded;
}
private Assembly LoadAssemble(object sender, ResolveEventArgs args)
{
string dllName = args.Name.Split(new char[] { ',' }).First();
Assembly tab = args.RequestingAssembly;
FileInfo fileInfo = new FileInfo(tab.Location);
DirectoryInfo dir = fileInfo.Directory;// new DirectoryInfo(path);
FileInfo[] files = dir.GetFiles("*.dll", SearchOption.TopDirectoryOnly);
foreach (FileInfo f in files)
{
if (f.Name.Contains(dllName))
{
Assembly ab = Assembly.LoadFile(f.FullName);
return ab;
}
}
return null;
}
}
本文版权归腿腿教学网及原创作者所有，未经授权，谢绝转载。
